DNH
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Tue, 28 Aug 2018 @ 01:41:10
Hi, could any one help me to crack this hash 202cb962ac59075b964b07152d234b7zero thanks in advanced..
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dipeperon
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Tue, 28 Aug 2018 @ 01:54:14
202cb962ac59075b964b07152d234b70 plaintext: 123 Next time please use the 25 hashes or less thread.
My haschat stuff (rules, scripts): https://github.com/theherp/Hashcat-stuff
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DNH
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Tue, 28 Aug 2018 @ 03:06:33
dipeperon said: 202cb962ac59075b964b07152d234b70 plaintext: 123 Next time please use the 25 hashes or less thread. sorry but this is wrong! 202cb962ac59075b964b07152d234b70 ---------------------------------- the hash will be : 202cb962ac59075b964b07152d234b7zero
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dipeperon
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Tue, 28 Aug 2018 @ 03:22:20
DNH said:
sorry but this is wrong!
202cb962ac59075b964b07152d234b70 ---------------------------------- the hash will be : 202cb962ac59075b964b07152d234b7zero
A hash is formatted as hexdigest to make it printable. I.e: every 1 byte [0-255] is converted to be 2 hex characters (16*16 = 256). z and r and o are not parts of the hex character set which is 0123456789abcdef, the hash that ends with "zero" is not a valid hash. Besides that the first 31 characters match the md5 of 123, which pretty much guarantees that the plaintext is 123.
My haschat stuff (rules, scripts): https://github.com/theherp/Hashcat-stuff
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Reconsniper
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Sat, 15 Sep 2018 @ 13:51:41
I confirm - 202cb962ac59075b964b07152d234b70:123
BTC:1BQRHfzASYYcaJmwEFDGwKE94wX1pWMaVA
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